CODEWITHSUNDEEP
javaandroidstring
sandalone
sandalone

Reputation: 41769

Remove a part of string via first and last character?

I am getting a HTML string as a result of querying a remote XML feed. I use the result to set text to a TextView. The problem is that a string contains HTML comment tags which are not supported by the TextView element.

Now, I need a way to remove (substring) the resulting string by indicating the part which will be removed. I cannot work via start and end positions, but I have to use starting and ending string pattern (<!-- as starting and --> as ending).

How can I do this?

Upvotes: 0

Views: 1052

Answers (5)

waqaslam
waqaslam

Reputation: 68187

perhaps use this:

String str = "your html string";
int start = str.indexOf("<!--");
int end = str.indexOf("-->");
str = str.replace(str.substring(start, (end - start)), "");

Upvotes: 1

Jave
Jave

Reputation: 31856

You can use the Html.fromHtml() method to use html-formatted text in a TextView, example:

CharSequence text = Html.fromHtml("before <!--comment--><b>after</b>");
myTextView.setText(text);

The TextView will now have the text "before after".

Upvotes: 0

Qiang Jin
Qiang Jin

Reputation: 4467

You can use regular express, e.g.

    String input = "<!-- \nto be removed -->hello <!-- to be removed-->world";
    Pattern pattern = Pattern.compile("<!--.*?-->", Pattern.DOTALL | Pattern.UNICODE_CASE | Pattern.MULTILINE);
    Matcher matcher = pattern.matcher(input);
    StringBuilder builder = new StringBuilder();
    int lastIndex = 0;
    while (matcher.find()) {
        builder.append(input.substring(lastIndex, matcher.start()));
        lastIndex = matcher.end();
    }
    builder.append(input.substring(lastIndex));
    System.out.println(builder);

Upvotes: 1

Thihara
Thihara

Reputation: 6969

I found this in here. I believe that since android is a tag here the answer will be relevant.

android.text.Html.fromHtml(instruction).toString()

Remove HTML tags from a String.

Upvotes: 1

Gaurav Agarwal
Gaurav Agarwal

Reputation: 19102

You can also use HTML.fromHTML

Upvotes: 0

Related Questions