Reputation: 89
I need to get the end date of the given month for some calculation purpose,
how can I do that in PHP, I tried using date() function, but It didn't work.
I used this:
date($year.'-'.$month.'-t');
But this gives the current month's end date. I think I'm wrong somewhere, I couldn't find where I'm going wrong here.
If I give year as 2012 & month as 03, then it must show me as 2012-03-31.
Upvotes: 0
Views: 3505
Reputation: 4765
If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
$a_date = "2012-03-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');
Upvotes: 0
Reputation: 2532
function getEndDate($year, $month)
{
$day = array(1=>31,2=>28,3=>31,4=>30,5=>31,6=>30,7=>31,8=>31,9=>30,10=>31,11=>30,12=>31);
if($year%100 == 0)
{
if($year%400 == 0)
$day[$month] = 29;
}
else if($year%4 == 0)
$day[$month] = 29;
return "{$year}-{$month}-{$day[$month]}";
}
Upvotes: 0
Reputation: 20269
You want to replace your date()
call with:
date('Y-m-t', strtotime($year.'-'.$month.'-01'));
The first parameter to date()
is the format you want to be returned, and the second parameter has to be a unix timestamp (or not passed to use the current timestamp). In your case, you can generate a timestamp with the function strtotime()
, passing it a date string with the year, the month, and 01 for the day. It will return that same year and month, but the -t
in the format will be replaced by the last day of the month.
If you want to return only the last day of the month without year and month:
date('t', strtotime($year.'-'.$month.'-01'));
Just use 't'
as your format string.
Upvotes: 2
Reputation: 522530
Current month:
echo date('Y-m-t');
Any month:
echo date('Y-m-t', strtotime("$year-$month-1"));
Upvotes: 1
Reputation: 60068
date("Y-m-d",strtotime("-1 day" ,strtotime("+1 month",strtotime(date("m")."-01-".date("Y")))));
Upvotes: 0
Reputation: 1568
function firstOfMonth() {
return date("Y-m-d", strtotime(date('m').'/01/'.date('Y').' 00:00:00')). 'T00:00:00';}
function lastOfMonth() {
return date("Y-m-d", strtotime('-1 second',strtotime('+1 month',strtotime(date('m').'/01/'.date('Y').' 00:00:00')))). 'T23:59:59';}
$date1 = firstOfMonth();
$date2 = lastOfMonth();
try this ,this give you a current month's starting and ending date.
Upvotes: 0
Reputation: 1336
This code will give you last day for a specific month.
$datetocheck = "2012-03-01";
$lastday = date('t',strtotime($datetocheck));
Upvotes: 4
Reputation: 484
function lastday($month = '', $year = '') {
if (empty($month)) {
$month = date('m');
}
if (empty($year)) {
$year = date('Y');
}
$result = strtotime("{$year}-{$month}-01");
$result = strtotime('-1 second', strtotime('+1 month', $result));
return date('Y-m-d', $result);
}
Upvotes: 0
Reputation: 1815
Try below code.
$m = '03';//
$y = '2012'; //
$first_date = date('Y-m-d',mktime(0, 0, 0, $m , 1, $y));
$last_day = date('t',strtotime($first_date));
$last_date = date('Y-m-d',mktime(0, 0, 0, $m ,$last_day, $y));
Upvotes: 0