Reputation: 589
So, I'm trying to write a simple class in Lua for representing CSV fields:
csv_entry = {}
csv_entry.__index = csv_entry
function csv_entry.create(...)
return arg
end
function csv_entry:tostring()
local str = string.char()
for i,v in ipairs(self) do
if i < #self then
str = str .. v
else
str = str .. v .. ", "
end
end
end
function csv_entry:print()
print(self:tostring())
end
But when I try to use this class like this:
c = csv_entry.create("Volvo", 10000, "Eric")
c:print() -- line 25
I get the error message
lua: csv.lua:25: attempt to call method 'print' (a nil value)
And I can't really figure out the issue here. What am I doing wrong?
Upvotes: 0
Views: 4916
Reputation: 520
I rewrite your code to meet what it is for, it runs OK for me:
csv_entry = {}
function csv_entry:create(...)
o = {content = {}}
self.__index = self;
setmetatable(o, self)
for i = 1, arg.n do
o.content[i] = arg[i];
end
return o;
end
function csv_entry:tostring()
local resStr = ""
for i, v in pairs(self.content) do
resStr = resStr .. v;
if i < #(self.content) then
resStr = resStr .. ", "
end
end
return resStr;
end
function csv_entry:print()
print(self:tostring())
end
c = csv_entry:create("Volvo", 10000, "Eric")
c:print()
Like @Mud said, the create(...) in your code is just a regular call and returns all arguments from ..., if you want csv_entry works like a class, then you have to put codes which set metatable and __index into create(...), and return an instance from csv_entry class
Upvotes: 0
Reputation: 29010
You probably meant to do is this:
function csv_entry.create(...)
return setmetatable(arg, csv_entry)
end
Your posted version of cvs_entry.create
just returns it's arguments packed into a table, so this code:
c = csv_entry.create("Volvo", 10000, "Eric")
c:print()
Is exactly equivalent to this code:
c = {"Volvo", 10000, "Eric"}
c:print()
c
doesn't contain a print
entry, so c.print
returns nil
and c:print()
fails because you're trying to "call" nil
.
Side note: the implicit arg
parameter to variadic functions was removed in Lua 5.1 (6 years ago). The correct way to do this now is:
function csv_entry.create(...)
local arg = {...}
return setmetatable(arg, csv_entry)
end
Or simply:
function csv_entry.create(...)
return setmetatable({...}, csv_entry)
end
As long as we're here: you're going to get no output from csv_entry:tostring
because it doesn't return anything. Also, if all you're trying to do is to concatenate a bunch of items with comma separators, you can use table.concat
:
function csv_entry:tostring()
return table.concat(self, ', ')
end
Upvotes: 3