CODEWITHSUNDEEP
c++visual-studio-2010
Oldemiro Henry Williams Baloi
Oldemiro Henry Williams Baloi

Reputation: 97

Nothing printed on array C++

I am new in C++. I generally program in C#, so I'm having troubles with arrays and loops. When I try to print content of dynamic array using a loop, it says corrupted requested area... For example I will give it recognize the condition used with content of array but doesn't print content of it:

// Array.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void main()
{
    int size=3;
    int *p;
    int myarray[10];
    myarray[3]=4;
    p=new int[size];
    p[2]=3;
    if(myarray[3]==4){
        cout << myarray[3] +"/n";
        cout << "Why?";
    }
    else
        cout << "Not equal " << endl;
    cin.get();
    delete [] p;
}

Upvotes: 0

Views: 167

Answers (3)

mwilliams
mwilliams

Reputation: 61

While a solution has been given:

cout << myarray[3] << "\n"

the point to get is that myarray[3] is an integer while "\n" is a string and the only way to "add" them together as strings is to first make the integer into a string. The << operator will handle the work of converting myarray[3] into a string, nothing special, and then the second << pumps a new line after it. I personally prefer code like this and find it more flexible, but it may be more that you're looking for at this stage of learning:

printf("%i\n", myarray[3]);

where printf searches for flags and loads in the other arguments as strings and outputs it in one command.

Upvotes: -1

Chip
Chip

Reputation: 3316

The problem is that myarray[3] +"\n".

"\n" represents the memory location of the string "\n". You are trying to add 4 to that location and printing it. This should give you junk data or a hardware exception (resulting in a coredump) if you are accessing a protected memory location.

To get what (i think) you are asking for do,

cout << myarray[3] << '\n'

Upvotes: 0

Blood
Blood

Reputation: 4186

Code looks fine, unless it should be

cout << myarray[3]  << "\n";

Not +

Upvotes: 7

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