Reputation: 28716
I have two models in SQLAlchemy, having a many-to-many relationship
team_user_table = Table('team_user', Base.metadata,
Column('user_id', Integer, ForeignKey('users.id')),
Column('team_id', Integer, ForeignKey('teams.id'))
)
class User(Base):
""" The SQLAlchemy declarative model class for a User object. """
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
name = Column(String, unique=True)
class Team(Base):
""" The SQLAlchemy declarative model class for a Team object. """
__tablename__ = 'teams'
id = Column(Integer, primary_key=True)
name = Column(Text, unique=True)
members = relationship("User",
secondary=team_user_table,
backref="memberteams")
I would like to query those users that are not member of a specific team.
In SQL (for example):
SELECT u.id,u.name FROM users u WHERE u.id NOT IN (SELECT tu.user_id FROM team_user tu WHERE tu.team_id=?);
How can I do this in SQLAlchemy?
Upvotes: 2
Views: 198
Reputation: 9722
I believe this should work and it does not use subqueries.
session.query(User).join(team_users_table).filter(team_users_table.team_id != OTHER_TEAM)
Upvotes: 0
Reputation: 7078
This does what you want:
team_id = 1
query = session.query(User.id).filter(~User.memberteams.any(Team.id == team_id))
This is the SQL it outputs (on MySQL):
SELECT users.id AS users_id, users.name AS users_name
FROM users
WHERE NOT (EXISTS (SELECT 1
FROM team_user, teams
WHERE users.id = team_user.user_id AND teams.id = team_user.team_id AND teams.id = %s))
This is not exactly what your query looks like now, but I think this is the way it should be done. Check the docs for this.
I tested this on MySQL. However, I think it should work on any other.
To have the exact query you are looking for, you might need to look into using subqueries in combination with the filter statement. I think you will need explicit reference to the team_user
table in your code to make it work.
Upvotes: 2