CODEWITHSUNDEEP
powershell
larryq
larryq

Reputation: 16309

Removing path and extension from filename in PowerShell

I have a series of strings which are full paths to files. I'd like to save just the filename, without the file extension and the leading path. So from this:

c:\temp\myfile.txt

to

myfile

I'm not actually iterating through a directory, in which case something like PowerShell's basename property could be used, but rather I'm dealing with strings alone.

Upvotes: 171

Views: 309160

Answers (14)

Papa Ccompis
Papa Ccompis

Reputation: 574

Expanding on René Nyffenegger's answer, for those who do not have access to a PowerShell version 6.0, or higher, we use Split Path, which doesn't test for file existence:

Split-Path "C:\Folder\SubFolder\myfile.txt" -Leaf

This returns "myfile.txt". If we know that the file name doesn't have periods in it, we can split the string and take the first part:

(Split-Path "C:\Folder\SubFolder\myfile.txt" -Leaf).Split('.') | Select -First 1

or

(Split-Path "C:\Folder\SubFolder\myfile.txt" -Leaf).Split('.')[0]

This returns "myfile". If the file name might include periods, to be safe, we could use the following:

$FileName = Split-Path "C:\Folder\SubFolder\myfile.txt.config.txt" -Leaf
$Extension = $FileName.Split('.') | Select -Last 1
$FileNameWoExt = $FileName.Substring(0, $FileName.Length - $Extension.Length - 1)

This returns "myfile.txt.config". Here I prefer to use Substring() instead of Replace() because the extension preceded by a period could also be part of the name, as in my example. By using Substring we return the filename without the extension as requested.

Upvotes: 11

Maybe
Maybe

Reputation: 1005

Here are a couple PowerShell 5.1 one-liner options that puts the path at the start of the line.

'c:\temp\myfile.txt' | Split-Path -Leaf

OR

'c:\temp\myfile.txt' -as [IO.FileInfo] | Select-Object -ExpandProperty BaseName

Upvotes: 2

Leonardo
Leonardo

Reputation: 2029

Way easier than I thought to address the issue of displaying the full path, directory, file name or file extension.

                                           ## Output:
$PSCommandPath                             ## C:\Users\user\Documents\code\ps\test.ps1
(Get-Item $PSCommandPath ).Extension       ## .ps1
(Get-Item $PSCommandPath ).Basename        ## test
(Get-Item $PSCommandPath ).Name            ## test.ps1
(Get-Item $PSCommandPath ).DirectoryName   ## C:\Users\user\Documents\code\ps
(Get-Item $PSCommandPath ).FullName        ## C:\Users\user\Documents\code\ps\test.ps1

$ConfigINI = (Get-Item $PSCommandPath ).DirectoryName+"\"+(Get-Item $PSCommandPath ).BaseName+".ini"

$ConfigINI                                 ## C:\Users\user\Documents\code\ps\test.ini

Other forms:

$scriptPath = split-path -parent $MyInvocation.MyCommand.Definition
split-path -parent $PSCommandPath
Split-Path $script:MyInvocation.MyCommand.Path
split-path -parent $MyInvocation.MyCommand.Definition
[io.path]::GetFileNameWithoutExtension($MyInvocation.MyCommand.Name)

Upvotes: 201

Benoit Deberdt
Benoit Deberdt

Reputation: 61

The command below will store in a variable all the file in your folder, matchting the extension ".txt":

$allfiles=Get-ChildItem -Path C:\temp\*" -Include *.txt
foreach ($file in $allfiles) {
    Write-Host $file
    Write-Host $file.name
    Write-Host $file.basename
}

$file gives the file with path, name and extension: c:\temp\myfile.txt

$file.name gives file name & extension: myfile.txt

$file.basename gives only filename: myfile

Upvotes: 2

user12386990
user12386990

Reputation: 31

This script searches in a folder and sub folders and rename files by removing their extension

    Get-ChildItem -Path "C:/" -Recurse -Filter *.wctc |

    Foreach-Object {

      rename-item $_.fullname -newname $_.basename

    }

Upvotes: 3

René Nyffenegger
René Nyffenegger

Reputation: 40603

Starting with PowerShell 6, you get the filename without extension like so:

split-path c:\temp\myfile.txt -leafBase

Upvotes: 18

user5062856
user5062856

Reputation:

This can be done by splitting the string a couple of times.

#Path
$Link = "http://some.url/some/path/file.name"

#Split path on "/"
#Results of split will look like this : 
# http:
#
# some.url
# some
# path
# file.name
$Split = $Link.Split("/")

#Count how many Split strings there are
#There are 6 strings that have been split in my example
$SplitCount = $Split.Count

#Select the last string
#Result of this selection : 
# file.name
$FilenameWithExtension = $Split[$SplitCount -1]

#Split filename on "."
#Result of this split : 
# file
# name
$FilenameWithExtensionSplit = $FilenameWithExtension.Split(".")

#Select the first half
#Result of this selection : 
# file
$FilenameWithoutExtension = $FilenameWithExtensionSplit[0]

#The filename without extension is in this variable now
# file
$FilenameWithoutExtension

Here is the code without comments : 

$Link = "http://some.url/some/path/file.name"
$Split = $Link.Split("/")
$SplitCount = $Split.Count
$FilenameWithExtension = $Split[$SplitCount -1]
$FilenameWithExtensionSplit = $FilenameWithExtension.Split(".")
$FilenameWithoutExtension = $FilenameWithExtensionSplit[0]
$FilenameWithoutExtension

Upvotes: 2

David A. Gray
David A. Gray

Reputation: 1075

Given any arbitrary path string, various static methods on the System.IO.Path object give the following results.

strTestPath                 = C:\Users\DAG\Documents\Articles_2018\NTFS_File_Times_in_CMD\PathStringInfo.ps1
GetDirectoryName            = C:\Users\DAG\Documents\Articles_2018\NTFS_File_Times_in_CMD
GetFileName                 = PathStringInfo.ps1
GetExtension                = .ps1
GetFileNameWithoutExtension = PathStringInfo

Following is the code that generated the above output.

[console]::Writeline( "strTestPath                 = {0}{1}" ,
                      $strTestPath , [Environment]::NewLine );
[console]::Writeline( "GetDirectoryName            = {0}" ,
                      [IO.Path]::GetDirectoryName( $strTestPath ) );
[console]::Writeline( "GetFileName                 = {0}" ,
                      [IO.Path]::GetFileName( $strTestPath ) );
[console]::Writeline( "GetExtension                = {0}" ,
                      [IO.Path]::GetExtension( $strTestPath ) );
[console]::Writeline( "GetFileNameWithoutExtension = {0}" ,
                      [IO.Path]::GetFileNameWithoutExtension( $strTestPath ) );

Writing and testing the script that generated the above uncovered some quirks about how PowerShell differs from C#, C, C++, the Windows NT command scripting language, and just about everything else with which I have any experience.

Upvotes: 4

CodeFox
CodeFox

Reputation: 3502

Inspired by an answer of @walid2mi:

(Get-Item 'c:\temp\myfile.txt').Basename

Please note: this only works if the given file really exists.

Upvotes: 74

walid2mi
walid2mi

Reputation: 2888

@Keith,

here another option:

PS II> $f="C:\Downloads\ReSharperSetup.7.0.97.60.msi"

PS II> $f.split('\')[-1] -replace '\.\w+$'

PS II> $f.Substring(0,$f.LastIndexOf('.')).split('\')[-1]

Upvotes: 8

Zombo
Zombo

Reputation: 1

Here is one without parentheses

[io.fileinfo] 'c:\temp\myfile.txt' | % basename

Upvotes: 3

walid2mi
walid2mi

Reputation: 2888

or

([io.fileinfo]"c:\temp\myfile.txt").basename

or

"c:\temp\myfile.txt".split('\.')[-2]

Upvotes: 37

walid2mi
walid2mi

Reputation: 2888

you can use basename property

PS II> ls *.ps1 | select basename

Upvotes: 28

Keith Hill
Keith Hill

Reputation: 202072

There's a handy .NET method for that:

C:\PS> [io.path]::GetFileNameWithoutExtension("c:\temp\myfile.txt")
myfile

Upvotes: 160

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