CODEWITHSUNDEEP
powershell
Mark Allison
Mark Allison

Reputation: 7228

How do I get a file path without extension in PowerShell?

I have an absolute path in a variable in my powershell 2.0 script. I want to strip off the extension but keep the full path and file name. Easiest way to do that?

So if I have C:\Temp\MyFolder\mytextfile.fake.ext.txt in a variable called, say $file

I want to return

C:\Temp\MyFolder\mytextfile.fake.ext

Upvotes: 18

Views: 39468

Answers (6)

FaniX
FaniX

Reputation: 375

Here is another solution using the .NET api, Path.ChangeExtension:

[System.IO.Path]::ChangeExtension($file, [NullString]::Value)

The second parameter must be explicitly specified as [NullString]::Value, since $null will be regarded as [String]::Empty ("") [1], which will leave an unwanted "." as the end.

PS> [System.IO.Path]::ChangeExtension("C:\Temp\MyFolder\mytextfile.fake.ext.txt",[NullString]::Value)
C:\Temp\MyFolder\mytextfile.fake.ext
PS> [System.IO.Path]::ChangeExtension("C:\Temp\MyFolder\mytextfile.fake.ext.txt",$null)
C:\Temp\MyFolder\mytextfile.fake.ext.

[1] PowerShell/PowerShell #4616

Upvotes: 0

Antebios
Antebios

Reputation: 1781

Here is the best way I prefer AND other examples:

$FileNamePath
(Get-Item $FileNamePath).Extension
(Get-Item $FileNamePath).Basename
(Get-Item $FileNamePath).Name
(Get-Item $FileNamePath).DirectoryName
(Get-Item $FileNamePath).FullName

Using these commands, the full path stripped by the extension is obtained as follows

$name = (Get-Item $file).Basename
$dir = (Get-Item $file).DirectoryName
$nameNoExt = "$dir\$name"

Upvotes: 24

Mehrdad Mirreza
Mehrdad Mirreza

Reputation: 1082

Regardless of whether $file is string or FileInfo object:

(Get-Item $file).BaseName

Upvotes: 3

Anthony Mastrean
Anthony Mastrean

Reputation: 22414

You should use the simple .NET framework method, instead of cobbling together path parts or doing replacements.

PS> [System.IO.Path]::GetFileNameWithoutExtension($file)

https://msdn.microsoft.com/en-us/library/system.io.path.getfilenamewithoutextension%28v=vs.110%29.aspx

Upvotes: 5

Roman Kuzmin
Roman Kuzmin

Reputation: 42083

# the path
$file = 'C:\Temp\MyFolder\mytextfile.fake.ext.txt'

# using regular expression
$file -replace '\.[^.\\/]+$'

# or using System.IO.Path (too verbose but useful to know)
Join-Path ([System.IO.Path]::GetDirectoryName($file)) ([System.IO.Path]::GetFileNameWithoutExtension($file))

Upvotes: 6

CB.
CB.

Reputation: 60976

if is a [string] type:

 $file.Substring(0, $file.LastIndexOf('.'))

if is a [system.io.fileinfo] type:

join-path $File.DirectoryName  $file.BaseName

or you can cast it:

join-path ([system.io.fileinfo]$File).DirectoryName  ([system.io.fileinfo]$file).BaseName

Upvotes: 31

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