CODEWITHSUNDEEP
jqueryarrays
moabi
moabi

Reputation: 1399

Array and elements with jQuery

I'm building an array with some elements like this : 

var listAccordions = [];
$("#accordeon ul.sub-menu.ui-accordion").each(function() { 
listAccordions.push("#" + $(this).parent().attr('id') + " ul.sub-menu");
});

everything works fine here, i've got my array and it's nice, now I want to use it like this : 

$( listAccordions ).hide();

but this doesn't seem to work ?

Thank you very much for your help

Upvotes: -1

Views: 71

Answers (5)

dfsq
dfsq

Reputation: 193261

You can do it like this:

$(listAccordions.join(',')).hide();

But the reasonable question: why would you need to have such a data structure?

Upvotes: 1

SamuGG
SamuGG

Reputation: 479

Try something like 

$(listAccordions).each(function() {
    $(this).hide();
}

Upvotes: 0

mplungjan
mplungjan

Reputation: 177692

$.each(listAccordions,function(i,item) {
  $("#"+item).hide();
});

will work. Your array is an array of strings

var listAccordions = [];
$("#accordeon ul.sub-menu.ui-accordion").each(function() { 
  listAccordions.push($("#" + $(this).parent().attr('id') + " ul.sub-menu"));
});

listAccordions.each(function() {
  $(this).hide()
});

should work too

Upvotes: 0

Diodeus - James MacFarlane
Diodeus - James MacFarlane

Reputation: 114347

listAccordions is in memory, not the DOM. You can add a class name to these elements, then use the class name to hide them - if you plan to use this collection for other things. Otherwise, hide them in the loop.

Upvotes: 0

Daniel A. White
Daniel A. White

Reputation: 190907

You will have to loop over listAccordions and call hide for each one.

for (var i = 0; i < listAccordions.length; i++) {
   $(listAccordions[i]).hide();
}

Upvotes: 0

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