CODEWITHSUNDEEP
c++boost
Benas Radzevicius
Benas Radzevicius

Reputation: 377

How to make a copy of bits with dynamic_bitset<>

I have this function: 

void SetCode(dynamic_bitset<> * c) {  
    this->_code = c;  
    this->_size = c->size();  
}

Where it says: this->_code = c, I want to make a copy of c and put it in this->_code.

How can i do this?

Upvotes: 0

Views: 544

Answers (1)

mauve
mauve

Reputation: 2016

Given that this->_code is the same dynamic_bitset<> as c. You can just use the assignment operator (this requires _code to already be initialized, i.e. newed):

*_code = *c;

You should probably remove the pointer from the type of this->_code and use a reference in the parameter instead:

class A {
public:
  void foo (boost::dynamic_bitset<T, U>& c)
  {
    _code = c;
  }

private:
  boost::dynamic_bitset<T, U> _code;
};

You didn't supply any of the template parameters for dynamic_bitset so I just chose two fake ones.

Upvotes: 1

Related Questions