CODEWITHSUNDEEP
c++boostbitsets
kal
kal

Reputation: 29353

dynamic_bit set print?

std::string charBuff = "11010";
dbitset = boost::dynamic_bitset<unsigned char> (charBuff);
for (boost::dynamic_bitset<>::size_type i = 0; i < dbitset.size(); ++i) {
      std::cout << dbitset[i];
}

It prints from the LSB to MSB. Output: 01011.

What should I do to so that bitset is printed correctly. I can reverse the character buffer which I am aware of :)

Upvotes: 0

Views: 1205

Answers (1)

dirkgently
dirkgently

Reputation: 111120

<unsigned car>

Should be:

<unsigned char>

What is buffer? Shouldn't you use charBuff?

Use the operator<< overload for dynamic_bitsets to achieve what you want. Here's a simplified solution:

#include <iostream>
#include <string>
#include <boost/dynamic_bitset.hpp>

int main()
{
    std::string charBuff("11010");
    boost::dynamic_bitset<> dbitset(charBuff);

    /* print LSB to MSB, in order */ 
    for (boost::dynamic_bitset<>::size_type i = 0; 
         i < dbitset.size(); ++i) {
        std::cout << dbitset[i];
    }
    std::cout << std::endl;

    /* print bits in the order you want */
    std::cout << dbitset << std::endl; 
    return 0;
}

Upvotes: 1

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