CODEWITHSUNDEEP
ruby
thefonso
thefonso

Reputation: 3390

if method_one returns value return value, else try method_two in ruby

How do I say if method_one returns a value, then break, else try method_two?

def ai_second_move(board)
  p "2nd move called"
  # TODO - how to say if method_one gives me a value, break, else method_two
  method_one(board)
  method_two(board) 
end

Upvotes: 0

Views: 82

Answers (4)

oldergod
oldergod

Reputation: 15010

You need to use return. break is for loops.

def ai_second_move(board)
  p "2nd move called"
  return if !!method_one(board)

  method_two(board) 
end

An other fun way would be

def ai_second_move(board)
  p "2nd move called"
  !!method_one(board) || method_two(board) 
end

Upvotes: 0

Stefan
Stefan

Reputation: 114218

This would work as well:

method_one(board) and return

The return statement is executed only if method_one(board) returns a truthy value.

Upvotes: 0

saihgala
saihgala

Reputation: 5774

using if -

method_two(board) if method_one(board).nil?

using unless - 

method_two(board) unless !method_one(board).nil?

using ternary -

# This evaluates if (method_one(board) returns nil) condition. If its true then next statement is method_two(board) else return is executed next.
method_one(board).nil? ? method_two(board) : return

Upvotes: 0

Laas
Laas

Reputation: 6078

Most Ruby way of writing this would be:

method_one(board) || method_two(board)

Ruby executes the right-hand side of || only if the left hand side evaluated to false (meaning it returns nil or false) and then the result of this expression would be that of the method_two

Upvotes: 7

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