CODEWITHSUNDEEP
pythonlistindexingrange
Charlie Kimzey
Charlie Kimzey

Reputation: 125

List index out of range (python)

I am creating a word generator for playing charades, and it works for about six words, then says "List index out of range."

this is my code:

def selection(word):
    while True:
        from random import randint
        sel = randint(1,10)
        print(word[sel])
        input("\nPress enter to select a new word.")

print("Type in ten words to add to the list.")
words = []
words.append(input("1st word: "))
words.append(input("2nd word: "))
words.append(input("3rd word: "))
words.append(input("4th word: "))
words.append(input("5th word: "))
words.append(input("6th word: "))
words.append(input("7th word: "))
words.append(input("8th word: "))
words.append(input("9th word: "))
words.append(input("10th word: "))
input("\nPress enter to randomly select a word.")
selection(words)

Upvotes: 0

Views: 1424

Answers (2)

Jakob Bowyer
Jakob Bowyer

Reputation: 34708

Also, not really an answer but you can do

for i in xrange(0, 9):
    words.append(input("{0}st word: ".format(i + 1))

Also

random.choice

Upvotes: 0

Tim
Tim

Reputation: 12174

You are currently picking a number between 1 and 10, inclusive. Python lists are 0 indexed, so you should be picking a number between 0 and 9.

sel = randint(0, 9)

This is also a good place to use the choice() function. It picks a random element from a sequence (eg a list).

random_word = random.choice(words)

Upvotes: 6

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