CODEWITHSUNDEEP
pythonlistindexing
GuangWu
GuangWu

Reputation: 143

list index out of range,python

I have a question, that is, I have 1D list like this:

List_A = []

and I also have another list, something like this:

List_B = [(1,2,3),(2,3,4),(3,4,5)]

Now I try to use:

for i in range(3):
List_A[i] = List_B[i][2]

which means, I want take every last (3rd) number from List_B to List_A, but it is said "index out of range", so what is the problem? Thank you very much for your helping

I know the append method but I think I can't use it, because my code is under a loop, the value in List_B changes in every step,something like:

List_A = []

for i in range(5):
List_B = [(i*1,i*2,i*3),(i*2,i*3,i*4),(i*3,i*4,i*5)]  
    for j in range(3):
        List_A[j] = List_B[j][2]

that is to say, if I use append method, the List_A will enlarge to 15 element size, but I need refresh value in every i loop.

Upvotes: 3

Views: 107

Answers (2)

Bhargav Rao
Bhargav Rao

Reputation: 52071

The problem is with List_A which has only one value. Here you are trying to change the values for the indexes 1 and 2 of the list where there is none. So you get the error.

Use append instead after declaring List_A as []

for i in range(3):
     List_A.append(List_B[i][2])

This can be done in a single list-comp as

List_A = [i[2] for i in List_B]

Post edit-

Put the initialization right after the first loop

for i in range(5):
    List_A = []                          # Here 
    List_B = [(1,2,3),(2,3,4),(3,4,5)]  
    for j in range(3):
        List_A.append(List_B[j][2])
    # Do other stuff

Upvotes: 5

Cory Kramer
Cory Kramer

Reputation: 117856

This loop is the problem

for i in range(3):
    List_A[i] = List_B[i][2]

You can only access List_A[0], the rest of the values of i are out of range. If you are trying to populate the list, you should use append

List_A = []
for i in range(3):
    List_A.append(List_B[i][2])

Or more Pythonic use a list comprehension

List_A = [i[2] for i in List_B]

Upvotes: 4

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