Reputation: 7639
I'm tring to remove the char '.' from a string except the last occurrence; for example the string
12.34.56.78
should became
123456.78
I'm using this loop:
while (value != null && value.Count(c => c == '.') > 1)
{
value = value.Substring(0, value.IndexOf('.')) + value.Substring(value.IndexOf('.') + 1);
}
I wonder if there is a cleaner way (maybe using linq?) to do this whitout an explicit loop?
(I know there is a very similar question but is about perl and things are quite different)
Upvotes: 3
Views: 3058
Reputation: 6615
you do not have to use loop:
//string val = "12345678";
string val = "12.34.56.78";
string ret = val;
int index = val.LastIndexOf(".");
if (index >= 0)
{
ret = val.Substring(0, index).Replace(".", "") + val.Substring(index);
}
Debug.WriteLine(ret);
Upvotes: 0
Reputation: 27618
Something like this should do the trick. Whether it is "good" or not is another matter. Note also that there is no error checking. Might want to check for null or empty string and that the string has at least one "."
in it.
string numbers = "12.34.56.78";
var parts = String.Split(new char [] {'.'});
string newNumbers = String.Join("",parts.Take(parts.Length-1)
.Concat(".")
.Concat(parts.Last());
I don't claim that this would have great performance characteristics for long strings, but it does use Linq ;-)
Upvotes: 1
Reputation: 460340
Perhaps a mixture of string
methods and Linq:
string str = "12.34.56.78";
Char replaceChar = '.';
int lastIndex = str.LastIndexOf(replaceChar);
if (lastIndex != -1)
{
IEnumerable<Char> chars = str
.Where((c, i) => c != replaceChar || i == lastIndex);
str = new string(chars.ToArray());
}
Upvotes: 6
Reputation: 50204
int lastIndex = value.LastIndexOf('.');
if (lastIndex > 0)
{
value = value.Substring(0, lastIndex).Replace(".", "")
+ value.Substring(lastIndex);
}
Upvotes: 5
Reputation: 6444
var splitResult = v.Split(new char[] { '.' }).ToList();
var lastSplit = splitResult.Last();
splitResult.RemoveAt(splitResult.Count - 1);
var output = string.Join("", splitResult) + "." + lastSplit;
I would do it that way. The neatest way isn't always the shortest way.
Upvotes: 1
Reputation: 2002
I would do that way:
OR
Upvotes: 1