sh script escaping

Question

From a linux terminal the command:

 ls application/js/{a*,b*,c*,d*,e.pocket-secure}

Will list all files in the application/js directory that start with a,b,c,d or e.pocket-secure.

If I place that command in doit.sh and execute:

sh doit.sh

I get:

ls: cannot access application/js/{a*,b*,c*,d*,e.pocket-secure*}: No such file or directory

I think the {} is confusing the shell interpreter, but I tried quoting (single|double) and also tried escaping the {} to no avail.

Answer 1

this syntax work only with bash interpretor you can try this

#/bin/bash
ls application/js/{a*,b*,c*,d*,e.pocket-secure}

and

chmod +x doit.sh
./doit.sh

OR

just type this on shell

bash doit.sh

Answer 2

When you type it in the terminal, I suspect that you are in bash. When you run sh doit.sh, you are changing the characteristics of the shell, either because bash is in compatibility mode or because you are using something like dash. Try doing bash doit.sh.