Reputation:
Edited*: I'm working on the delete function for a binary search tree. I'm just working on the first case right now. I think this is correct, but I'm wondering if it can be done recursively, or more efficiently. Any help is appreciated. Assume BSTSearch searches for a node, isLeaf
returns true if the node is a leaf, and each node has a pointer that allows them access to their parent.
void
BinarySearchTree::BSTDelete(int x, BSTNode *node){
BSTNode *deleteNode;
deleteNode = BSTSearch(x,node);
if(isLeaf(deleteNode)){
if(deleteNode->sortkey > (deleteNode->parent)->sortkey){
delete (deleteNode->parent)->right;
(deleteNode->parent)->right = NULL;
}
else{
delete (deleteNode->parent)->left;
(deleteNode->parent)->left = NULL;
}
}
Upvotes: 0
Views: 4511
Reputation: 55589
You don't need a pointer to the parent. Here is a recursive version that should work: (pass by reference (&
), in case you don't know, allows you to modify the variable, similar to pass by pointer; BSTNode *&
is a pointer passed by reference, so we can modify the value of node->left/right (pointers) (not just what they're pointing to))
void BinarySearchTree::BSTDelete(int x, BSTNode *&node)
{
if (node == NULL)
return;
if (x == node->sortKey)
{
if (isLeaf(node))
{
delete node;
node = NULL;
}
else
{
// other stuff goes here
}
return;
}
else if (x < node->sortKey)
BSTDelete(x, node->left);
else
BSTDelete(x, node->right);
}
Upvotes: 2