CODEWITHSUNDEEP
css
Andrew
Andrew

Reputation: 14526

Applying a single background gradient to a table row

Is it possible to have a background gradient that spans an entire table row? I'm only able to apply the background to individual table cells, even when I'm specifically trying to prevent that. Here is a boiled-down sample that targets Webkit on jsfiddle:

http://jsfiddle.net/cGV47/2/

As you can see, I am using border-collapse:collapse and I am specifying background:transparent for the <tr> and <th> child elements, yet the red gradient to the left is repeated for each table cell. I've tried applying the background to the <tr> as well, but with the same result as you see now.

To view the code without going to jsfiddle, here it is:

html

<table>
    <thead>
        <tr>
            <th>One</th>
            <th>Two</th>
            <th>Three</th>
            <th>Four</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>un</td>
            <td>deux</td>
            <td>trois</td>
            <td>quatre</td>
        </tr>
    </tbody>
</table>

css

* {margin:0;padding:0;border:0;border-collapse:collapse;}
table { width:100%; }
thead { background: -webkit-linear-gradient(left, rgba(222,22,22,1) 0%, rgba(222,222,222,0) 20%, rgba(222,222,222,0) 80%, rgba(222,222,222,1) 100%); }
thead tr, thead th { background:transparent; }

Upvotes: 31

Views: 35947

Answers (4)

Slyy
Slyy

Reputation: 21

I have found myself testing the brand new repeating-linear-gradient, which apparently works for <tr> elements (I have only tested in Google Chrome though).

The trick is to provide the widest repeating pattern, so that... it does not repeat.

Try this:

tr {
    background: repeating-linear-gradient(
        45deg,
        red 0%,
        blue 100%
    );
}

http://jsfiddle.net/slyy/2pzwws0d/

Upvotes: 2

jekcom
jekcom

Reputation: 2095

set background-attachment:fixed; on thead and it will work fine

http://jsfiddle.net/cGV47/64/

Upvotes: 44

Moises Garcia
Moises Garcia

Reputation: 99

I think there is a better solution to these:

  • Apply the gradient background to the whole table.
  • Then apply a solid background for thead and tfooter.

table { border:0; border-collapse:collapse;
    background: -moz-linear-gradient(left,  rgba(255,255,255,1) 0%, rgba(108,211,229,0.2) 40%, rgba(108,211,229,0.2) 60%, rgba(255,255,255,1) 100%); /* FF3.6+ */
    background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(255,255,255,1)), color-stop(40%,rgba(108,211,229,0.2)), color-stop(60%,rgba(108,211,229,0.2)), color-stop(100%,rgba(255,255,255,1))); /* Chrome,Safari4+ */
    background: -webkit-linear-gradient(left,  rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* Chrome10+,Safari5.1+ */
    background: -o-linear-gradient(left,  rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* Opera 11.10+ */
    background: -ms-linear-gradient(left,  rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* IE10+ */
    background: linear-gradient(to right,  rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* W3C */
    filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#ffffff',GradientType=1 ); /* IE6-9 */            
}

table thead, tfoot {
    background: #fff;
}

Take a look: http://jsfiddle.net/5brPL/

Upvotes: 7

matthewpavkov
matthewpavkov

Reputation: 2928

Not the prettiest solution, but it does do the trick. You just set up each th to have 25% of the color range. The example below uses a color range from 0 to 255.

http://jsfiddle.net/cGV47/3/

Same HTML that you already have. Here's the CSS:

table { width:100%; }

th {
    background: -webkit-linear-gradient(left, rgba(255,255,255,1) 0%, 
                                              rgba(191,191,191,1) 100%);
}
th + th {
    background: -webkit-linear-gradient(left, rgba(191,191,191,1) 0%, 
                                              rgba(128,128,128,1) 100%);
}
th + th + th {
    background: -webkit-linear-gradient(left, rgba(128,128,128,1) 0%, 
                                              rgba(64,64,64,1) 100%);
}
th + th + th + th {
    background: -webkit-linear-gradient(left, rgba(64,64,64,1) 0%, 
                                              rgba(0,0,0,1) 100%);
}

I found this issue on Google: http://code.google.com/p/chromium/issues/detail?id=122988 but there is no solution.

Firefox does not have this issue (didn't check any other browsers):
http://jsfiddle.net/cGV47/4/

Upvotes: 0

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