Reputation: 339
I'm putting together a table with 6 columns, and I'm trying to see if I can apply 1 continuous gradient to the 1st column. I know that I can select the first column with either :first-child
or :first-of-type
or :nth-child(1)
, but using any other these would apply the gradient to just that cell, causing a ripple effect on the column. Is there a way to select the WHOLE column, and apply one single, flowing gradient?
Here is my jsFiddle
I only included 2 columns. 1 Column for the gradient, and 1 other dummy column to show how other columns wouldn't be affected.
Upvotes: 0
Views: 1889
Reputation: 106008
If you use the tag <col/>
you may draw backgrounds from there and so, different backgrounds for each col, ... as long as it is not hidden by a tr
or `td/th background. https://jsfiddle.net/0cxn599p/5/
table#compare {
border-spacing: 0px;
margin-bottom: 25px;
background-color: #2e6ca8;
}
table#compare .features {
color: white;
text-align: right;
padding: 10px 15px 10px;
width: 200px;
}
/* rgba colors can be used over btable background and col background */
tr:nth-child(odd) {/* DEMO */
background: rgba(0, 0, 0, 0.1);
}
tr:nth-child(even) :first-child {/* DEMO */
background: rgba(255,255,255, 0.1);
}
.dark-blue-grad {
min-width: 10em;
/* this works too */
background-image: -webkit-linear-gradient(#4897e4, #2e6ca8);
background-image: -o-linear-gradient(#4897e4, #2e6ca8);
background-image: -moz-linear-gradient(#4897e4, #2e6ca8);
background-image: linear-gradient(#4897e4, #2e6ca8);
background-color: #4897e4;
}
<table id="compare">
<colgroup>
<col/>
<col class="dark-blue-grad" />
<col/>
</colgroup>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
<td class="features">Feature #2</td>
</tr>
</table>
Upvotes: 1
Reputation: 19007
Here is a Working Fiddle
The idea is to set the gradient to the Table
and then make the first column background transparent and the 2nd column background White.
table#compare {
border-spacing: 0px;
margin-bottom: 25px;
}
table#compare .features {
background-color: transparent;
color: white;
text-align: right;
padding: 10px 15px 10px;
width: 200px;
}
table#compare tr:nth-child(1) .features {
border-radius: 4px 4px 0px 0px;
}
table#compare tr td:nth-child(2){
background-color:white;
}
.box {
height: 100px;
width: 100px;
}
.dark-blue-grad, #compare {
background-image: -webkit-linear-gradient(#4897e4, #2e6ca8);
background-image: -o-linear-gradient(#4897e4, #2e6ca8);
background-image: -moz-linear-gradient(#4897e4, #2e6ca8);
background-image: linear-gradient(#4897e4, #2e6ca8);
background-image: #4897e4;
}
<table id="compare">
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
<tr>
<td class="features">Feature #1</td>
<td>Other column</td>
</tr>
</table>
<div class="dark-blue-grad box">
</div>
Upvotes: 2