Reputation: 10342
I have a menu item in my overflow menu with no icon at all and I am using it as an information to the user which should not have been seen right away.
When I make it disabled, it will be greyed out. I want to make an item that is not clickable? How can I do that? Thank you.
Upvotes: 3
Views: 1316
Reputation: 6857
In order to achieve this, you should specify your own style for ListView
item with selector
:
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_window_focused="false" android:state_enabled="true"
android:drawable="@drawable/btn_default_normal" />
<item android:state_window_focused="false" android:state_enabled="false"
android:drawable="@drawable/btn_default_normal" />
<item android:state_pressed="true"
android:drawable="@drawable/btn_default_pressed" />
<item android:state_focused="true" android:state_enabled="true"
android:drawable="@drawable/btn_default_selected" />
<item android:state_enabled="true"
android:drawable="@drawable/btn_default_normal" />
<item android:state_focused="true"
android:drawable="@drawable/btn_default_normal_disable_focused" />
<item
android:drawable="@drawable/btn_default_normal" />
</selector>
It is a code taken from default button's xml. I changed it so that in state android:state_enabled="false"
it still uses normal background.
You can change it to whatever you want your item to look like.
Put it into xml file called for example my_item.xml
, put it into drawable directory and then in xml where you create your item, set it's background to background="@drawable/my_item"
.
Upvotes: 2