CODEWITHSUNDEEP
javaregex
James Raitsev
James Raitsev

Reputation: 96491

Regex to validate url with port, clarification needed

I am trying to match a URL using the following regex, in Java

^http(s*):\\/\\/.+:[1-65535]/v2/.+/component/.+$

Test fails using URL: https://box:1234/v2/something/component/a/b

I suspect it's the number range that's causing it. Help me understand what am i missing here please?

Upvotes: 0

Views: 2827

Answers (3)

v01pe
v01pe

Reputation: 1136

The group [1-65535] basically means number from 1 to 6 or 5 or 5 or 3 or 5. that would even evaluate, but you need an + (or *) at the end of the group.

To match the port more precisely you could use [1-6][0-9]{0,4}?. That would get you really close, but also allow p.e. 69999 - the {m,n}? is used to specify how often a group can be used (m to n times)

Also take care of that (s*) thing the others pointed out!

That would result in: ^https?:\\/\\/.+:[1-6][0-9]{0,4}?/v2/.+/component/.+$

Upvotes: 1

Fredrick Brennan
Fredrick Brennan

Reputation: 7357

See http://www.regular-expressions.info/numericranges.html. You can't just write [1-65535] to match 1 or 65535. That says any number 1-6, or 5 or 3.

The expression you need is quite verbose, in this case:

([1-9][0-9]{0,3}|[1-5][0-9]{4}|6[0-4][0-9]{3}|65[0-4][0-9]{2}|655[0-2][0-9]|6553[0-5])

(Credit to http://utilitymill.com/utility/Regex_For_Range)

Another issue is your http(s*). That needs to be https? because in its current form it might allow httpsssssssss://. If your regex takes public input, this is a concern.

Upvotes: 4

Adrián
Adrián

Reputation: 6255

^http(s*) is wrong, it would allow httpssssss://...

You need ^https?

This doesn't affect the given test though.

Upvotes: 2

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