CODEWITHSUNDEEP
xsltmatch
J R
J R

Reputation: 49

Insert XPath during copy using apply-templates

I've created an XSLT using an identity template and several templates that match to a potential XPath in the source. However, the matching paths do not always exist. Is there a way to "insert" the path before the matching template applies? Since I know XSLT does not execute procedurally, I wasn't sure how to do this. Examples below.

Let's say this is the XSLT:

<xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:if>
</xsl:template>

<xsl:template match='pathA'>
   do stuff
</xsl:template>

<xsl:template match='pathB'>
  do something
</xsl:template>

<xsl:template match='pathC'>
   do other stuff
</xsl:template>

And let's say this in the input:

<root>
    <Child>
        <pathA>I have Data!</pathA>
        <pathC>We skipped B!</pathC>
    </Child>
</root>

Is there a way to "create" pathB so that the template that matches the XPath can execute?

Thanks again for any assistance!

Upvotes: 1

Views: 265

Answers (1)

minopret
minopret

Reputation: 4806

Good one. How about...

<xsl:template name="pathB">
    <xsl:param name="nodes"/>
    do something 
</xsl:template>


<xsl:template match="Child">
    <xsl:copy>
        <xsl:apply-templates select="@* | pathA[not(../pathB)] | pathB/preceding-sibling::node()"/>
    </xsl:copy>

   <xsl:call-template name="pathB">
       <!-- pass the set of elements of type "pathB", possibly an empty nodeset -->
       <xsl:with-param name="nodes" select="pathB"/>
   </xsl:call-template>

    <xsl:copy>
        <xsl:apply-templates select="node()[not(self::pathA) and not(../pathB)] | pathB/following-sibling::node()"/>
    </xsl:copy>
<xsl:template>

Upvotes: 1

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