CODEWITHSUNDEEP
javahibernatemappedsuperclass
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Reputation: 3177

How to override parameter in sublass of @MappedSuperclass

I have a MappedSuperclass

@MappedSuperclass
public class A{
    .
    .
    .
    @Column(name="something")
    public getSomething(){..};
    public setSomething(){..};
}

I want to override the something in a subclass

@Entity
public class B{
    @Override
    public getSomething(){..};
}

but getting Caused by: org.hibernate.MappingException: Duplicate property mapping of data found Exception

I tried different things like "@AttributeOverride" annotation, but it didn't help.

The only solution i know is to make something Transient in the mappedSuperclass. But i don't want that it will be transient here (because there is another subclasses that don't want to override something but want that it will be transient)

Upvotes: 3

Views: 1544

Answers (1)

WPrecht
WPrecht

Reputation: 1382

Two solutions occur to me: one is to maybe break this SuperClass up and use Emmbeddeds to create the hierarchy you want. If you want to stick with this approach though, I think you need to override using @AttributeOverride both the property and the method like this in the subclass:

@Entity
public class B {

    @AttributeOverride(name = "fred", column = @Column(name = "FRED"))
    private Integer fred;

    @Override
    public Integer getFred() {return fred;}
}

Upvotes: 3

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