CODEWITHSUNDEEP
cwindowswinapi
user2129387
user2129387

Reputation: 19

How to delay(backcount) in c?

Can anyone show me how to delay or back count in c ? I mean write 1 and 2 after a second. The only way I know is

include<windows.h>

Sleep( 1000 /* milliseconds */ );

can anyone please show me another way to do this? (I have windows 8)

Upvotes: 2

Views: 363

Answers (4)

alk
alk

Reputation: 70883

The use of select() would be another, and also portable solution, although quite unconventional approach to (just) generate a delay.

Upvotes: 0

Zeta
Zeta

Reputation: 105876

You can use thrd_sleep, which is available in C11, and write a simple wrapper for it:

void sleep(time_t seconds){
    struct timespec ts, remaining;
    timespec_get(&ts, TIME_UTC);
    ts.tv_sec += seconds;
    while(thrd_sleep(&ts,&remaining) == -1){
        timespec_get(&ts, TIME_UTC);
        ts.tv_sec += remaining.tv_sec;
    }
}

Upvotes: 2

alk
alk

Reputation: 70883

Set an alarm using alarm() to be fired a second later then call pause().

Upvotes: 1

pmg
pmg

Reputation: 108967

If you're limited to Standard C89

#include <stdio.h>
#include <time.h>

int main(void) {
    time_t t;

    /* wait until the Standard clock ticks */
    t = time(0);
    while (time(0) == t) /* void */;

    /* print 1 */
    puts("1");

    /* wait until the Standard clock ticks again */
    t = time(0);
    while (time(0) == t) /* void */;

    /* print 2 */
    puts("2");

    return 0;
}

If you can use POSIX: use nanosleep().

Upvotes: 2

Related Questions