CODEWITHSUNDEEP
iphoneobjective-cnsstring
ttotto
ttotto

Reputation: 837

How to parse numbers from NSString?

NSString *numberVector = @"( 1, 2, 3, 4)";

I want to get NSMutableArray from these numbers. How can I do this?

Upvotes: 1

Views: 297

Answers (5)

CainaSouza
CainaSouza

Reputation: 1437

With this:

NSString *numberVector = @"( 1, 2, 3, 4)";

EDIT

NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"&([^;])*;" options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [numberVector stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];

NSArray *listItems = [[modifiedString stringByTrimmingCharactersInSet:[NSCharacterSet newlineCharacterSet]] componentsSeparatedByString:@", "]

Upvotes: -2

Balu
Balu

Reputation: 8460

try like this it'l works fine for any type of data it accepts only numbers.

NSString *numberVector = @"(\n 1,\n 2,\n 3,\n 4\n)";

    NSString *onlyNumbers = [numberVector  stringByReplacingOccurrencesOfString:@"[^0-9,]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, [numberVector  length])];
    NSArray *numbers=[onlyNumbers componentsSeparatedByString:@","];
    NSLog(@"%@",numbers);

Upvotes: 1

Inder Kumar Rathore
Inder Kumar Rathore

Reputation: 39988

This is the simpler one, convert it to json string first then convert is to array using NSJSONSerialization

NSString *numberVector = @"( 1, 2, 3, 4)";
numberVector = [numberVector stringByReplacingOccurrencesOfString:@"(" withString:@"["];
numberVector = [numberVector stringByReplacingOccurrencesOfString:@")" withString:@"]"];
NSError* error;
NSMutableArray *arr = [NSJSONSerialization JSONObjectWithData:[numberVector dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableContainers error:&error];

Update

This will work for both @"( 1, 2, 3, 4)" and @"(\n 1,\n 2,\n 3,\n 4\n)" as json string can have new line and spaces.

P.S This will work for iOS 5.0 or greater for other iOS you can use SBJSON or other parsing library available.

Upvotes: 3

C0L.PAN1C
C0L.PAN1C

Reputation: 12243

See the code below, it should work:

  NSCharacterSet *cSet = [NSCharacterSet characterSetWithCharactersInString:@" ()"];  
  numberVector = [numberVector stringByTrimmingCharactersInSet:cSet];
  //specify delimiter below
  NSArray *numbers = [numberVector componentsSeparatedByString:@", "];

Upvotes: 0

DrummerB
DrummerB

Reputation: 40211

If you know that this is exactly your format and don't have to be flexible in the amount of spaces, brackets or commas:

NSCharacterSet *trimSet = [NSCharacterSet characterSetWithCharactersInString:@" ()"];
numberVector = [numberVector stringByTrimmingCharactersInSet:trimSet];
NSArray *numbers = [numberVector componentsSeparatedByString:@", "];

Upvotes: 1

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