CODEWITHSUNDEEP
cmakefileexecutable
Don Jano
Don Jano

Reputation: 33

Generating DIFFERENT executable from different files using ONE Makefile

I have three files written in C: 

a.c, b.c, d.c

I want to use ONE Makefile to generate independent executable files from them, like this: 

a.x, b.x d.x.

They don't need each other to run. They are completely different programs.

I know, I can write a line to compile each one of them, like this:

gcc -Wall -Werror a.c -o a.x
gcc -Wall -Werror b.c -o b.x
gcc -Wall -Werror d.c -o d.x

But I am searching for an easier solution to do this independently from the number of files, due to the fact, that in the future I am going to have a lot of them.

I have an original that looks like this:

CC = gcc
CFLAGS = -g -Wall - Werror -03
%.x:%.c
    ${CC} {CFLAGS} -o $@ $<
clean: 
    rm -f *.o

But I don't know, how to customize it, so that it read each one of my c-files and generate a x-file from each one of them.

Thanks

Upvotes: 3

Views: 891

Answers (1)

Jim Balter
Jim Balter

Reputation: 16406

Have you tried adding

all: a.x b.x c.x

in front of your makefile?

all: a.x b.x c.x

CC = gcc
CFLAGS = -g -Wall - Werror -03
%.x:%.c
    ${CC} {CFLAGS} -o $@ $<
clean: 
    rm -f *.o

Edit: To build all the .c files in the directory, try

all: $(*.c:.c=.x)

I'm quite rusty on Make so this might not quite be right ... You should read the Make documentation.

Edit 2: Indeed that wasn't right ... this is more likely to work:

SRCS = *.c

all: $(SRCS:.c=.x)

Or

SRCS = *.c
PGMS = $(SRCS:.c=.x)

all: $PGMS

Upvotes: 5

Related Questions