CODEWITHSUNDEEP
xsltxpath
Irwene
Irwene

Reputation: 3035

How to get childs nodes when we don't know their names

I have to work on XML files on which i won't know the names of the nodes. All i know is that the structure will be the same between the different files

The structure will be the above one

<root>
    <node1>
        <node2>
        </node2>
    </node2>
</root>

I have to make an XSLT file for building an HTML page that will display the content of the nodes.

For now i have this piece of code

<xsl:template match="/">
<html>
  <head>
    <link rel="stylesheet" type="text/css" href="employe.css"/>
  </head>
  <body>
    <table>
      <tr>
        <th>ID Source</th>
        <th>Nom</th>
        <th>Prénom</th>
        <th>Age</th>
        <th>Adresse</th>
        <th>Code Postal</th>
        <th>Ville</th>
        <th>Telephone</th>
        <th>Poste</th>
      </tr>
      <xsl:apply-templates/>
    </table>
  </body>
</html>
</xsl:template>

<xsl:template match="child::*">
    <tr>
        <xsl:apply-templates/>
    </tr>
</xsl:template>

<xsl:template match="">
    <td>
        <xsl:value-of select="."/>
    </td>
</xsl:template>

I succeeded in selecting the first and the second level nodes but don't know how to select the third.

Thanks for help

Upvotes: 1

Views: 104

Answers (1)

Daniel Haley
Daniel Haley

Reputation: 52878

You could try changing the match="/" to match="/*" and adding these two templates:

<xsl:template match="*[*]">
    <tr>
        <xsl:apply-templates/>
    </tr>
</xsl:template>

<xsl:template match="*[not(*)]">
    <td><xsl:value-of select="."/></td>
</xsl:template>

Upvotes: 2

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