mani bharataraju
mani bharataraju

Reputation: 162

conversion of .wav to array

import java.io.BufferedInputStream;
import java.io.ByteArrayOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;

import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.UnsupportedAudioFileException;


public class Audio_to_bytes {

    public static void main(String args[]) throws IOException
{
    File WAV_FILE = new File("/home/cybersecurity/Desktop/scream.wav");
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    AudioInputStream in = null;
    try {
        in = AudioSystem.getAudioInputStream(WAV_FILE);
    } catch (UnsupportedAudioFileException e) {

        e.printStackTrace();
    } catch (IOException e) {

        e.printStackTrace();
    }


    int read,i;
    byte[] buff = new byte[1024];
    while ((read = in.read(buff)) > 0)
    {
        out.write(buff, 0, read);
    }
    out.flush();
    byte[] audioBytes = out.toByteArray();
    for(i=0;i<audioBytes.length;i++)
        System.out.println(audioBytes[i]);
}
}

The above code is to convert the .wav file into a byte array.When I execute the program i get get many value as -128 or -127,I want to know that whether these values are exact values or the value becomes a boundary value if it exceeds the range of byte(-128 to 128), if so can i convert the audio file into a integer array since it has a wider range.

Upvotes: 1

Views: 1405

Answers (1)

Buhake Sindi
Buhake Sindi

Reputation: 89169

The raw file is irrelevant since WAVE files are constructed using chunks. I suggest understanding those chunks first, RIFF File Format, to understand WAVE files.

Upvotes: 2

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