CODEWITHSUNDEEP
pythonlist
user2113818
user2113818

Reputation: 827

putting individual lists on new lines

Bloody stupid question from dead brain...

I have a list:

[1,2,3,4,5,6,7,8,9]

which I sliced up into 3 lists:

splits = [1,2,3],[4,5,6],[7,8,9]

which I would like to now have printed on individual lines such that 

print splits

gives 

[1,2,3]
[4,5,6]
[7,8,9]

Can someone please 1) whack me upside the head and 2) remind me how to do this?

Upvotes: 1

Views: 82

Answers (4)

Levon
Levon

Reputation: 143027

If 

s = [[1,2,3],[4,5,6],[7,8,9]] # list of lists

or

s = [1,2,3],[4,5,6],[7,8,9]   # a tuple of lists

then 

for i in s:
   print(i)

will result in:

[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

Guided by the Zen of Python: Simple is better than complex.

Upvotes: 6

Jacob Valenta
Jacob Valenta

Reputation: 6769

Is the 3 lists a list of lists? ex [[1],[2],[3]]?

if so, just:

for sliced_list in list_of_lists:
    print(sliced_list)

With your given syntax [1,2,3],[4,5,6],[7,8,9], it is a tuple of lists , which will behave the same when using the for statement.

Upvotes: 2

Sheng
Sheng

Reputation: 3555

I do not understand your first quesion.

For the second one, you might like to do it like:

>>> splits = [1,2,3],[4,5,6],[7,8,9]
>>> print "\n".join([repr(item) for item in splits])
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

Upvotes: 0

user206545
user206545

Reputation:

Use the string join function:

print '\n'.join(str(x) for x in [[1,2,3],[4,5,6],[7,8,9]])

Upvotes: 0

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