CODEWITHSUNDEEP
pythonregex
Kirk ERW
Kirk ERW

Reputation: 167

Regular expression to extract a message

i have a script that read lines of files.. and some of the lines contain Error messages.. so i have made a loop ( here it's just for one line ) to find those lines and extract the messages: 

import re

data = "15:31:17 TPP    E Line 'MESSAGE': There is a technical problem in the server."

if (re.findall(".*E Line.*",data)):
    err = re.match(r'\'MESSAGE\':\s(*$)',data)
    print err

I have and error when i execute this script :/ i'd like it to return: 

There is a technical problem in the server

Upvotes: 2

Views: 100

Answers (2)

Inbar Rose
Inbar Rose

Reputation: 43447

You don't need a regular expression for this if they all follow the same format:

>>> data = "15:31:17 TPP    E Line 'MESSAGE': There is a technical problem in the server."
>>> data.rsplit(':', 1)[1]
' There is a technical problem in the server.'

But if you must use them...

>>> data = "15:31:17 TPP    E Line 'MESSAGE': There is a technical problem in the server."
>>> ms = re.search(r"'MESSAGE': (.*)$", data)
>>> ms.group(1)
'There is a technical problem in the server.'

If you wanted you could extract other information as well:

>>> ms = re.match(r"(\d\d:\d\d:\d\d)\s+(\S+)\s+(\S+)\s+Line\s+'MESSAGE':\s+(.*)", data)
>>> ms.groups()
('15:31:17', 'TPP', 'E', 'There is a technical problem in the server.')

Upvotes: 4

user1220978
user1220978

Reputation:

Try this:

import re

data = "15:31:17 TPP    E Line 'MESSAGE': There is a technical problem in the server."

r = re.compile("^.*E Line.*'MESSAGE':[ ]*([^ ].*)$")
m = r.match(data)
if m:
    err = m.group(1)
    print(err)

Of course you should compile the regex outside of the loop.

Upvotes: 1

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