CODEWITHSUNDEEP
python
Monique Williams
Monique Williams

Reputation: 33

Function that takes a string as input and counts the number of times the vowel occurs in the string

So I am very new to python and am in the process of learning the basics. I am trying to create a function the counts the number of vowels in a string and returns how many times each vowel occurs in the string. For example if I gave it this input, this is what it would print out.

   >>>countVowels('Le Tour de France') 
       a, e, i, o, and u appear, respectively, 1,3,0,1,1 times.

I made this helper function to use, but then I'm not exactly sure how to use it.

def find_vowels(sentence):
count = 0
vowels = "aeiuoAEIOU"
for letter in sentence:
    if letter in vowels:
        count += 1
print count

And then I thought that maybe I could use formatting to get them in the write places, but I am not sure the notation that would be used for example, one of the lines for the function could be: 

   'a, , i, o, and u appear, respectively, {(count1)}, {(count2)}, {(count3)}, {(count4)}, {(count5)} times'

I am not sure how I would be able to fit the above in the function.

Upvotes: 1

Views: 16801

Answers (3)

Gameatro
Gameatro

Reputation: 153

a =input("Enter string: ")
vowels = sum([a.lower().count(i) for i in "aeiou"])
print(vowels)

This also works. dont know if it is more or less efficient. it makes list for each of aeiou and sums it

Upvotes: 0

jhoyla
jhoyla

Reputation: 1251

An easier answer would be to use the Counter class.

def count_vowels(s):
    from collections import Counter
    #Creates a Counter c, holding the number of occurrences of each letter 
    c = Counter(s.lower())
    #Returns a dictionary holding the counts of each vowel
    return {vowel:c[vowel] for vowel in 'aeiou'}

Upvotes: 1

AI Generated Response
AI Generated Response

Reputation: 8845

You'd need to use a dictionary to store the values, since if you directly add the counts you lose information about exactly which vowel you are counting.

def countVowels(s):
    s = s.lower() #so you don't have to worry about upper and lower cases
    vowels = 'aeiou'
    return {vowel:s.count(vowel) for vowel in vowels} #a bit inefficient, but easy to understand

An alternate method would be:

def countVowels(s):
    s = s.lower()
    vowels = {'a':0,'e':0,'i':0,'o':0,'u':0}
    for char in s:
        if char in vowels:
            vowels[char]+=1
    return vowels

to print this, you would do this:

def printResults(result_dict):
    print "a, e, i, o, u, appear, respectively, {a},{e},{i},{o},{u} times".format(**result_dict)

Upvotes: 2

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