CODEWITHSUNDEEP
pythonparameters
Timothy
Timothy

Reputation: 4487

How to transfer all the elements of a list into a function which asks for *args?

I'm invoking a third-party function with the head like def foo(*args), so that ordinarily I can use it in this way foo(a,b,c).

But now I have a list, say li = [a,b,c]. I don't know how many elements it has until runtime. How to transfer all the elements of the list into the function foo as parameters.

I've tried foo(li) and foo(tuple(li)), but they don't work. Please help.

Thank you.

Upvotes: 0

Views: 105

Answers (2)

Ashwini Chaudhary
Ashwini Chaudhary

Reputation: 250961

use * while calling the function, * is used for unpacking a sequence into separate positional arguments during function call:

foo(*li)

demo:

>>> def foo(*args): print (args)
>>> foo(*range(10))
(0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

Upvotes: 2

Sadjad
Sadjad

Reputation: 1670

Try passing li with an * before it as in foo(*li):

li = [1, 2, 3, 4, 5]
foo(*li)

For example:

>>> def f(*args):
...     print args
...
>>> li = [1,2,3]
>>> f(*li)
(1, 2, 3)

Upvotes: 2

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