CODEWITHSUNDEEP
pythonfunctionargumentsargument-passing
Milano
Milano

Reputation: 18735

Passing *arg arguments from list

I'm in a situation when I have to call one function foo:

def foo(arg1,arg2,*args):
    pass

The problem is that I have the *args arguments stored during computing as a list.

Like this:

a = 'arg1'
b = 'arg2'
list_of_args = ['arg3','arg4','arg5']

How can I call the function foo with this arguments to be like:

foo('arg1','arg2','arg3','arg4','arg5')

I could do this:

foo(a,b,list_of_args[0],list_of_args[1],list_of_args[2])

but it does not solve this problem because length of list_of_args depends on a situation so it could be:

foo(a,b,list_of_args[0],list_of_args[1],list_of_args[2],list_of_args[3],...)

Upvotes: 0

Views: 38

Answers (1)

user2555451
user2555451

Reputation:

Simply unpack the list with *:

a = 'arg1'
b = 'arg2'
list_of_args = ['arg3','arg4','arg5']

foo(a, b, *list_of_args)

From the docs:

If the syntax *expression appears in the function call, expression must evaluate to an iterable. Elements from this iterable are treated as if they were additional positional arguments

Upvotes: 1

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