Reputation: 1883
I understand this could appear alarming but bear with me.
I need to echo every field in every row in a table.
This is only an example - I have removed the HTML wrapped around it to improve readability.
$a = 1;
while ($a <= $count_rows) {
$query = "SELECT col1, col2 etc.. FROM table WHERE `id`='$id'";
$result = mysqli_query($con, $query);
$i = 1;
while($i <= $count_fields) {
$row = mysqli_fetch_array($result, MYSQL_NUM);
echo "$row[$i]";
$i++;
}
$a++;
$id = $a;
}
This only outputs the first field of every row? Why?
If I echo $row[2]
I get nothing!
Upvotes: 0
Views: 1196
Reputation: 157889
If I echo $row[2] I get nothing!
because it's actually third item
and there is some strange code interfering with $i variable
Anyway, to get every column from every row ou need a code like this
$query = "SELECT * FROM table";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_row($result)) {
foreach ($row as $index => $value) {
echo "$index => $value, ";
}
echo "<br>\n";
}
Upvotes: 2