CODEWITHSUNDEEP
javastringbufferedreader
aqua
aqua

Reputation: 739

Java-Convert String to int when using BufferedReader

How do you convert a String to int when using BufferedReader? as far as i remember,its something like below:

System.out.println("input a number");

int n=Integer.parseInt(br.readLine(System.in));

but for some reason,its not working.

the error message says:

no suitable method found for readLine(java.io.InputStream)

it also says br.readLine is not applicable

Upvotes: 8

Views: 76820

Answers (6)

user4387809
user4387809

Reputation: 1

DataInputStream br=new DataInputStream(System.in);
System.out.println("input a number");
int n=Integer.parseInt(br.readLine(System.in));

Upvotes: -1

Kevin Bowersox
Kevin Bowersox

Reputation: 94459

An InputStreamReader needs to be specified in the constructor for the BufferedReader. The InputStreamReader turns the byte streams to character streams. As others have mentioned be cognizant of the exceptions that can be thrown from this piece of code such as an IOException and a NumberFormatException.

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("input a number");
int n = Integer.parseInt(br.readLine());

Upvotes: 19

drew moore
drew moore

Reputation: 32680

Try this:

  BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
   System.out.println("input a number");
try{  
    int n = Integer.parseInt(br.readLine());
    } catch (IOException e) {e.printStackTrace();}

Upvotes: 0

Sanjaya Liyanage
Sanjaya Liyanage

Reputation: 4746

try this way

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
 String input = reader.readLine();
 int n=Integer.parseInt(input);

Upvotes: 1

KhAn SaAb
KhAn SaAb

Reputation: 5366

try this

BufferedReader br = new BufferedReader(System.in);
String a=br.readLine()
Integer x = Integer.valueOf(a);
System.out.println(x);//integer value

Upvotes: 1

Konstantin Yovkov
Konstantin Yovkov

Reputation: 62864

When using BufferedReader you have to take care of the exceptions it may throw. Also, the Integer.parseInt(String s) method may throw an NumberFormatException if the String you're providing cannot be converted to Integer.

try {
   BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
   while ((thisLine = br.readLine()) != null) {
     System.out.println(thisLine);
     Integer parsed = Integer.parseInt(thisLine);
     System.out.println("Parsed integer = " + parsed);
   } 
 } catch (IOException e) {
    System.err.println("Error: " + e);
 } catch (NumberFormatException e) {
    System.err.println("Invalid number");
 }

Upvotes: 1

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