CODEWITHSUNDEEP
javastringbufferedreadertext-parsing
Bálint Hartyányi
Bálint Hartyányi

Reputation: 13

String to int with BufferedReader

I have this code but when I try to run it I got this error Exception in thread "main" java.lang.NumberFormatException: For input string: "1" Every line is contains a number a name an email and a date so the first character in every line is the number. The tomb[0] is just a number

List<Szemely> lista = new ArrayList<>();
try (BufferedReader br = new BufferedReader(new FileReader(this.szemelyekcsv))) {
            String line;

            while ((line = br.readLine()) != null) {
                String[] tomb;
                tomb = line.split(";");

               int sor = Integer.parseInt(tomb [0]);
                DateTimeFormatter sima = DateTimeFormatter.ofPattern("yyyy-MM-dd");
                LocalDate szul = LocalDate.parse(tomb[3], sima);


                lista.add(new Szemely(sor, tomb[1], tomb[2], szul));

            }
        } catch (FileNotFoundException ex) {
            System.out.println("Nem tudom megnyitni a 'be.txt' fájlt.");
        } catch (IOException ex) {
            System.out.println("Hiba a 'be.txt' fájl olvasása közben.");
        }

when the program reach this line

int sor = Integer.parseInt(tomb [0]);

automaticly jump back to 

try (BufferedReader br = new BufferedReader(new FileReader(this.szemelyekcsv)))

and error... thanks all help.

Upvotes: 0

Views: 270

Answers (1)

maraca
maraca

Reputation: 8743

As pooyan, AxelH and VGR pointed out the problem was indeed one or more invisible characters (e.g. control characters).

One way to solve this is cut away everything that's not a digit using regular expressions:

int sor = Integer.parseInt(tomb[0].replaceAll("[^0-9]+", ""));

[^...] = not those characters

[0-9] = digits

+ = one or more times

Upvotes: 2

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