CODEWITHSUNDEEP
pythonarraysnumpyminimum
Makaroni
Makaroni

Reputation: 912

minimum of array of floats in python

How can I find minimum of array of floats in Python? The min() or array.min() did not work. Here is the code:

import numpy as np

z=np.array([[ -4.26141957e-01],
       [ -2.26582552e-01],
       [ -7.28807682e-03],
       [  2.72843324e-02],
       [ -5.59146620e-02],
       [ -2.06062340e-05],
       [  1.06954166e-09],
       [ -6.34170623e-01],
       [  5.07841198e-02],
       [ -1.89888605e-04]])

z_min=z.min()

which gives z_min = -0.63417062312627426. I am a Matlab user so this is confusing to me...

Upvotes: 1

Views: 657

Answers (2)

chenaren
chenaren

Reputation: 2268

z_min = -0.63417062312627426 looks like the right answer. Be careful about scientific notation.

Upvotes: 5

Geoff
Geoff

Reputation: 8145

np.min() returns the smallest number, or the "largest" negative number (if there are any). In this case the entry at index 7 is the minimum entry. It is -6.34 * 10^-1 in scientific notation, or -0.634... in long-hand.

Printing all in long-hand

Perhaps this will help:

print "\n".join(["%+0.10f" % e for e in z])

-0.4261419570
-0.2265825520
-0.0072880768
+0.0272843324
-0.0559146620
-0.0000206062
+0.0000000011
-0.6341706230
+0.0507841198
-0.0001898886

To verify your answer

The following will show that only one entry has this minimum value.

z <= z.min()

array([[False],
       [False],
       [False],
       [False],
       [False],
       [False],
       [False],
       [ True],
       [False],
       [False]], dtype=bool)

One more example

The number closest to zero can be found like this:

z[np.abs(z).argmin()]

Which is 1.06954166e-09 = 1.069 * 10^-09 in scientific notation or 0.000000000106... in long-hand.

Upvotes: 3

Related Questions