Reputation: 149
I can't seemn to make this work could someone help identify what is incorrect:
$result = mysql_query("SELECT accounts_client_email.client_email FROM accounts_client_email WHERE accounts_client_email.accounts_client_id = 1", $con);
while( $row = mysql_fetch_assoc( $result)){
$new_array[] = $row; // Inside while loop
}
$tags = implode(', ', array($new_array));
echo $tags;
Upvotes: 0
Views: 158
Reputation: 1647
If you just need a comma separated string, not an array, you can do it like this:
while( $row = mysql_fetch_assoc( $result))
{
if(empty($tags)
$tags = $row['client_email'];
else
$tags .= ', '.$row['client_email'];
}
echo $tags; //will display comma separated string - no arrays needed
Upvotes: 0
Reputation: 26
use for loop
$array_to_string="";
for($i=0;$i<=count($result_array)-1;$i++)
{
if($i != count($result_array)-1)
{
$array_to_string .= $result_array[$i].",";
}else
{
$array_to_string .= $result_array[$i];
}
}
echo $array_to_string; // you get the string as a commoa seperated values which is available in the array
Upvotes: 0
Reputation: 610
You need to use brackets
$new_array[] = $row[]; // Inside while loop
If this doesnt work, use
$new_array[] = $row['client_email']; // Inside while loop
Upvotes: 1
Reputation: 23480
I think you just need to use scope with your column name to populate in your array
while( $row = mysql_fetch_assoc( $result))
{
$new_array[] = $row['client_email']; // Inside while loop
}
I would like to also to remember you that mysql_*
functions are officially deprecated and no longer maintained so i would advise you to switch to mysqli
or PDO
for new projects.
Upvotes: 1
Reputation: 4844
You aren't adding correctly to the array, it should be:
$new_array[] = $row['client_email'];
And you are encapsulating the array into another array unnecessarily;
use:
$tags = implode(', ', $new_array);
Or echo $tags;
will just output "Array"
Upvotes: 1