CODEWITHSUNDEEP
javascriptregex
chromedude
chromedude

Reputation: 4302

How can you make a Javascript Regex only match when two characters are beside each other?

I have a regex to split a paragraph into sentences: 

var sentences = /[^\.!\?]+[\.!\?]+/g;

I would like it only to match if the punctuation ([\.!\?]+) has a whitespace \s after it. I tried /[^\.!\?]+[\.!\?]+\s/g, but that did not work.

The reason why I want this is because currently if there is a word with punctuation in the middle (like about.me) it is splitting it there like the . represents the end of a sentence when it does not. Any ideas?

For example:

If I have this paragraph:

If the problem being solved isn't as apparent or immediately useful as traffic about.me and navigation data: weather. A few apps are trying to harness the crowd to provide accurate?

I want it to only split into

['If the problem being solved isn't as apparent or immediately useful as traffic about.me and navigation data: weather.', 'A few apps are trying to harness the crowd to provide accurate?']

whereas currently it splits into

['If the problem being solved isn't as apparent or immediately useful as traffic about.', 'me and navigation data: weather.', 'A few apps are trying to harness the crowd to provide accurate?'].

Upvotes: 0

Views: 115

Answers (2)

AntouanK
AntouanK

Reputation: 4968

Is this what you want?

var str = "If the problem being solved isn't as apparent or immediately useful as traffic about.me and navigation data: weather. A few apps are trying to harness the crowd to provide accurate?";

str.match(/.+?(\.|\?)(\s|$)/g);

Upvotes: 2

Graham
Graham

Reputation: 6562

Use lookahead:

var re = /[\.!\?]+(?=\s)/g;

var result = "If the problem being solved isn't as apparent or immediately useful as traffic about.me and navigation data: weather. A few apps are trying to harness the crowd to provide accurate?".split(re);

console.log(result.length);  // => 2

Upvotes: 1

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