CODEWITHSUNDEEP
bashfunctionif-statementtoken
user2495181
user2495181

Reputation: 11

Syntax error near

For quite some time now I have been struggling with this little code segment.

#!/bin/bash

testFunction() { 

        if [ -d "/home/$USER/.skandPATH/" ] ; then 
                #Exists. Do nothing. 
        else 
                mkdir /home/$USER/.skandPATH/   #Does not exist. Creates directory 
                addedPathDir=1 
        fi
} 

testFunction

Every time I run it I get the following message:

./functionInScript.sh: line 7: syntax error near unexpected token `else'
./functionInScript.sh: line 7: `else '

I've searched through dozens of "syntax error near unexpected token bash" and tried dozens of suggestions.

I have run dos2unix (even though I'm using Mint) on the file. I have escaped the dots in ".skandPATH" but that doesn't seem to make a difference. I have tried deleting every whitespace character and tab character. I have tried commenting out lines and executed the script in order to try and pinpoint the problem, to no avail. I'm at my wits end trying to find what's wrong here!

If you could help me... I would be most grateful.

Upvotes: 0

Views: 750

Answers (2)

Rudy Matela
Rudy Matela

Reputation: 6480

Why not:

#!/bin/bash

testFunction() { 
    if ! [ -d "/home/$USER/.skandPATH/" ] ; then 
            mkdir /home/$USER/.skandPATH/
            addedPathDir=1
    fi
} 

testFunction

Upvotes: 2

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799062

You must have at least one command in a block; try :.

Upvotes: 5

Related Questions