Reputation: 2250
I have an excel file that is 126 rows and 5 columns full of numbers, I have to use that data and SVD methods to predict 5-10 more rows of data. I have implemented SVD in Python successfully using numpy:
import numpy as np from numpy import genfromtxt
my_data = genfromtxt('data.csv', delimiter=',')
U, s, V = np.linalg.svd(my_data)
print ("U:")
print (U)
print ("\nSigma:")
print (s)
print ("\nVT:")
print (V)
which outputs:
U:
[[-0.03339497 0.10018171 0.01013636 ..., -0.10076323 -0.09740801
-0.08901366]
[-0.02881809 0.0992715 -0.01239945 ..., -0.02920558 -0.04133748
-0.06100236]
[-0.02501102 0.10637736 -0.0528663 ..., -0.0885227 -0.05408083
-0.01678337]
...,
[-0.02418483 0.10993637 0.05200962 ..., 0.9734676 -0.01866914
-0.00870467]
[-0.02944344 0.10238372 0.02009676 ..., -0.01948701 0.98455034
-0.00975614]
[-0.03109401 0.0973963 -0.0279125 ..., -0.01072974 -0.0109425
0.98929811]]
Sigma:
[ 252943.48015512 74965.29844851 15170.76769244 4357.38062076
3934.63212778]
VT:
[[-0.16143572 -0.22105626 -0.93558846 -0.14545156 -0.16908786]
[ 0.5073101 0.40240734 -0.34460639 0.45443181 0.50541365]
[-0.11561044 0.87141558 -0.07426656 -0.26914744 -0.38641073]
[ 0.63320943 -0.09361249 0.00794671 -0.75788695 0.12580436]
[-0.54977724 0.14516905 -0.01849291 -0.35426346 0.74217676]]
But I am not sure how to use this data to preidct my values. I am using this link http://datascientistinsights.com/2013/02/17/single-value-decomposition-a-golfers-tutotial/ as a reference but that is in R. At the end they use R to predict values but they use this command in R:
approxGolf_1 <- golfSVD$u[,1] %*% t(golfSVD$v[,1]) * golfSVD$d[1]
Here is the IdeOne link to the entire R code: http://ideone.com/Yj3y6j
I'm not really familiar with R so can anyone let me know if there is a similar function in Python to the command above or explain what that command is doing exactly?
Thanks.
Upvotes: 0
Views: 1649
Reputation: 8900
I will use the golf course example data you linked, to set the stage:
import numpy as np
A=np.matrix((4,4,3,4,4,3,4,2,5,4,5,3,5,4,5,4,4,5,5,5,2,4,4,4,3,4,5))
A=A.reshape((3,9)).T
This gives you the original 9 rows, 3 columns table with scores of 9 holes for 3 players:
matrix([[4, 4, 5],
[4, 5, 5],
[3, 3, 2],
[4, 5, 4],
[4, 4, 4],
[3, 5, 4],
[4, 4, 3],
[2, 4, 4],
[5, 5, 5]])
Now the singular value decomposition:
U, s, V = np.linalg.svd(A)
The most important thing to investigate is the vector s
of singular values:
array([ 21.11673273, 2.0140035 , 1.423864 ])
It shows that the first value is much bigger than the others, indicating that the corresponding Truncated SVD with only one value represents the original matrix A
quite well. To calculate this representation, you take column 1 of U
multiplied by the first row of V
, multiplied by the first singular value. This is what the last cited command in R does. Here is the same in Python:
U[:,0]*s[0]*V[0,:]
And here is the result of this product:
matrix([[ 3.95411864, 4.64939923, 4.34718814],
[ 4.28153222, 5.03438425, 4.70714912],
[ 2.42985854, 2.85711772, 2.67140498],
[ 3.97540054, 4.67442327, 4.37058562],
[ 3.64798696, 4.28943826, 4.01062464],
[ 3.69694905, 4.3470097 , 4.06445393],
[ 3.34185528, 3.92947728, 3.67406114],
[ 3.09108399, 3.63461111, 3.39836128],
[ 4.5599837 , 5.36179782, 5.0132808 ]])
Concerning the vector factors U[:,0]
and V[0,:]
: Figuratively speaking, U
can be seen as a representation of a hole's difficulty, while V
encodes a player's strength.
Upvotes: 1