CODEWITHSUNDEEP
batch-file
jam
jam

Reputation: 3688

Extract part of a path in batch

What's the simplest way in batch to get part of a path?

From other 'suggested questions' I'm now aware of ~dp0, but it seems like that only works on the current working directory?

I want to get a substring out of an environment variable, instead. Specifically, everything up to the final \.

In bash, I can do this with newpath=${fullpath%\\*}, is there an equivalently simple batch construct?

Upvotes: 2

Views: 1452

Answers (3)

foxidrive
foxidrive

Reputation: 41287

Here is a method to eliminate a trailing backslash from an environment variable:

@echo off
set "var=c:\program files\rock & roll\"
for /f "delims=" %%a in ("%var%\.") do echo set "var=%%~fa"
pause

Upvotes: 1

David Ruhmann
David Ruhmann

Reputation: 11367

From how I read your question, you want the parent directory for the specified path.

Building on what RGuggisberg answered you can do something like this.

@echo off
call :Parent "%~dp0"
exit /b 0

:Parent <Path>
pushd "%~f1\.." || exit /b 1
echo %CD%
popd
exit /b 0

Upvotes: 1

RGuggisberg
RGuggisberg

Reputation: 4750

Below is one way to do it (assuming variable fullpath contains path). This works whether there is a trailing \ or not. Another way is to trim the last character, but that assumes you always have a trailing \, which you may not??? Of course you may want to store %cd% in some other variable instead of echoing it.

pushd %fullpath%
echo.%cd%
popd

Upvotes: 0

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