Reputation: 181
Say I have a list of numbers such as:
my_list = [1, 17, 2]
And I wanted to add those together. I know I can use print(sum(my_list))
. However I wanted to see if there was another way of doing so, so I tried the following:
b = len(my_list)
for m in range(my_list[0], my_list[b-1]):
m += m
print(m)
I am sure something like this should work, but I am obviously doing it wrong. The output of this is 2
. After I tried:
result = 0
b = len(my_list)
for m in range(my_list[0], my_list[b-1]):
result = result + m
print(result)
This outputs 1
.
Please explain what I am doing wrong and how I can correct it.
Upvotes: 1
Views: 5499
Reputation: 1
to get the values from my_list you can use this syntax:
for m in my_list:
print m
If you use range it will give you a range from 1 ( first value of your list ) to 2 (length of your list -1)
To add the values of your list you can try this code:
out = 0
for m in my_list:
out = out + m
print(out)
Upvotes: 0
Reputation: 186803
First, you should put a correct range: 0..2 in your case (since your list items' indexes starts from 0 and has 2 items)
for i in range(0, b):
result = result + my_list[i];
Or if you prefer "for each" style you should itterate by list you are summing:
for m in my_list:
result = result + m;
Finally if you want to print a final sum only you should correct print indent:
for m in my_list:
result = result + m;
print(result) # <- mind indent
Wrapping up:
my_list = [1, 17, 2]
result = 0
for m in my_list:
result = result + m;
print(result)
Upvotes: 2
Reputation: 1806
Since you are using range function defining range between 1 and 2. The only data generated in m is 1 hence result is 1.
In Python, you can iterate over the elements of a sequence directly:
m = [1, 17, 2]
res = 0
for i in m:
res += i
print res
Upvotes: 3
Reputation: 387
from operator import add
my_list = [1, 17, 2]
result=reduce(add, my_list)
Upvotes: 2