CODEWITHSUNDEEP
regexcoffeescript
noMAD
noMAD

Reputation: 7844

Regex for one word in sentence

So I am trying to match a (any) word(s) that would have:

  1. At least one upper case letter
  2. At least one lower case letter
  3. At least one number

I currently got to this using lookaheads

^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).+$

But I am not able to get this to match on one word. I tried to use \b around the lookaheads but it doesn't work. The thing the word that I am trying to match on can have the above conditions in any order. Example: aB5 OR Ba5 OR 5Ba etc.. Need some pointers.

Upvotes: 2

Views: 1489

Answers (2)

Bernhard Barker
Bernhard Barker

Reputation: 55609

The main problem is that . includes spaces. You need to change your .'s to be restricted to word-characters only, i.e. \w. Note that \w is (mostly) [A-Za-z0-9_], if you wish to exclude some of these or include more, you should make the appropriate changes.

Another thing is that if you're looking for words in a string, you need to remove ^ and $ because these mean the start and end of the string respectively.

Since all your requirements are "at least" (as opposed to "at most"), you don't really need \b because of matching happens left-to-right, so you can never get part of a word.

Regex:

(?=\w*\d)(?=\w*[a-z])(?=\w*[A-Z])\w+

Test.

Upvotes: 3

Bergi
Bergi

Reputation: 664559

I currently got to this using lookaheads

^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).+$

But I am not able to get this to match on one word.

Lookaheads are the correct approach, but if you want to find single words only you must not allow every character (.) in between but only word-characters (like \w). So

/(?=\w*\d)(?=\w*[a-z])(?=.\w[A-Z])\w+/g

should do it. Of course you're free to allow more letters than only \w, maybe even \S.

Upvotes: 2

Related Questions