Reputation: 85
I created a custom URL handler that runs my Java application successfully (that is an exe file generated after maven buid). Below is what I did and added the handler to registery.
Windows Registry Editor Version 5.00
[HKEY_CLASSES_ROOT\my]
@="URL:my Protocol"
"URL Protocol"=""
[HKEY_CLASSES_ROOT\my\shell]
@="open"
[HKEY_CLASSES_ROOT\my\shell\open\command]
@="\"C:\\myApp.exe\""
[HKEY_CLASSES_ROOT\my\shell\open\ddeexec]
@=""
"NoActivateHandler"=""
and in my test.html, I have
<a href="my:go/id=guest">My Application Start</a>
How can I get the parameter pass(id in the link) passed from URL inside the application?
Upvotes: 3
Views: 1094
Reputation: 85
What I used to register :
[HKEY_CLASSES_ROOT\myApp]
@="URL:myApp Protocol handled by CustomURL"
"URL Protocol"=""
"CustomUrlApplication"="C:\\temp\\eclipse.exe"
[HKEY_CLASSES_ROOT\myApp\DefaultIcon]
@="C:\\temp\\eclipse.exe"
[HKEY_CLASSES_ROOT\myApp\shell]
[HKEY_CLASSES_ROOT\myApp\shell\open]
[HKEY_CLASSES_ROOT\myApp\shell\open\command]
@="C:\\temp\\eclipse.exe %1"
the link in my html file looking like this :
<a href="myApp:go/USER">Application Start</a>
then I could get whole link inside my application via :
String[] args = Platform.getCommandLineArgs();
Upvotes: 1