Reputation: 21
I am using the GLFW and only want to open a empty windows.
I downloaded the GLFW for Windows 32. Created an empty console project and wrote this code:
#include "main.h"
#pragma comment (lib, "glfw3dll")
#pragma comment (lib, "OpenGL32")
#define GLFW_DLL
#include <glfw3.h>
#include <chrono>
#include <iostream>
using namespace std::chrono;
GLFWwindow* window;
bool running = true;
bool initialise(){
return true;
}
void update(double deltaTime){
}
void render(){
}
int main(int argc, char **argv) {
if (!glfwInit)
return -1;
window = (glfwCreateWindow(800, 600, "Hello World", nullptr, nullptr));
if (window == nullptr){
glfwTerminate();
return -1;
}
glfwMakeContextCurrent(window);
if (!initialise()){
glfwTerminate();
return -1;
}
auto currentTimeStamp = system_clock::now();
auto prevTimeStamp = system_clock::now();
while (running)
{
currentTimeStamp = system_clock::now();
auto elapsed = duration_cast<milliseconds>(currentTimeStamp - prevTimeStamp);
auto seconds = double(elapsed.count()) / 1000.0;
update(seconds);
render();
glfwPollEvents();
prevTimeStamp = currentTimeStamp;
}
glfwTerminate();
return -1;
}
And I think I added the library and the header correctly. But everytime the programm exits with -1 after the glfwCreateWindow(..) function, because this functions return null.
Can somebody help me?
Upvotes: 1
Views: 4428
Reputation: 52083
if (!glfwInit)
return -1;
I'm not sure why glfwInit
would be NULL
unless something truly terrible happened during DLL load.
Try calling glfwInit()
instead:
if( !glfwInit() )
return -1;
Upvotes: 3