Reputation: 806
I want to set set the border color white for linear layout but no inner color.
Here is my code that display the inner color black. Where is the mistake?
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:left="0dp" android:right="0dp" android:top="-10dp" android:bottom="-10dp">
<shape android:shape="rectangle">
<stroke android:width="1dp" android:color="#ffffff" />
</shape>
</item>
</layer-list>
Upvotes: 1
Views: 5583
Reputation: 1351
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle"
>
<solid android:color="color_that_u_want_in background" />
<stroke android:width="1dp"
android:color="#ffffff"/>
</shape>
use this
Upvotes: 0
Reputation: 2664
Set this to your LinearLayout background
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" >
<stroke
android:width="1dp"
android:color="#ffffff" />
<solid android:color="#000000" />
</shape>
Upvotes: 0
Reputation: 83028
Add <solid android:color="@android:color/transparent" />
into shape tag.
<shape android:shape="rectangle" >
<solid android:color="@android:color/transparent" />
</shape>
Upvotes: 3
Reputation: 4222
android:color="#ffffff"
should be:
android:color="#000000"
The current color code is set to white instead of black.
Upvotes: 0