CODEWITHSUNDEEP
pythonstringdictionary
Karyo
Karyo

Reputation: 372

python count repeating characters in a string by using dictionary function

I have a string

string = 'AAA'

When using the string.count('A') the output is equal to 3 and if it is string.count('AA') the output is equal to 1

However, there are 2 'AA's in the string.

Is there any method to count repeated string like above by using dictionary function?

I'd like to hear your helpful suggestions.

Thank you all in advance.

Upvotes: 1

Views: 6869

Answers (3)

getflag
getflag

Reputation: 53

Yeah! You can use a dictionary

def count(input):

    a = {}

    for i in input:
        a[i] = a.get(i,0)+ 1
    return a

print(count('AA')) #Would return 2

Upvotes: -1

Marco Mariani
Marco Mariani

Reputation: 13776

Alternative for "not huge" strings

>>> s, sub = 'AAA', 'AA'
>>> sum(s[x:].startswith(sub) for x in range(len(s)))
2

I find this a little more readable.

Upvotes: 1

Kobi K
Kobi K

Reputation: 7929

The problem is Count return the number of (non-overlapping) occurrences of substring sub in string.

try this as you can see at this post:

def occurrences(string, sub):
    count = start = 0
    while True:
        start = string.find(sub, start) + 1
        if start > 0:
            count+=1
        else:
            return count

Upvotes: 1

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