CODEWITHSUNDEEP
python-3.xstringdictionary
Shakiib
Shakiib

Reputation: 57

count the frequency of each character using the dictionary in python

My program that takes a string as an input from the user and counts the frequency of each character using the dictionary. Input:

Python programming is fun

Expected output:

{'p': 2, 'y': 1, 't': 1, 'h': 1, 'o': 2, 'n': 3, 'r': 2, 'g': 2, 'a': 1, 'm': 2, 'i': 2, 's': 1, 'f': 1, 'u': 1}

My code:

string = input().lower()
dicx = {}
count = 0
for i in string:
    dicx['i'] = ''

print(dicx)

Upvotes: 0

Views: 11992

Answers (6)

Wayne Gan
Wayne Gan

Reputation: 37

d = {}
test_str = input().lower()

for x in test_str:
    d[x] = d.get(x,0) + 1
print(d)

much more elegant like this

Upvotes: 0

apayziev
apayziev

Reputation: 3

def charCounter(string):
    empty = {}
    for i in string.lower():
        if i in empty.keys():
            empty[i] += 1
        else:
            empty[i] = 1
    return empty

print(charCounter("Oh, it is python"))

Upvotes: 0

Raymond Reddington
Raymond Reddington

Reputation: 1837

Way 1: For

    symbols = {}
    for s in inp_str.lower():
        if s in symbols:
            symbols[s] += 1
        else:
            symbols.update({s: 1})
    print(symbols)

Way 2: defaultdict

     symbols = defaultdict(int)
     for s in inp_str.lower():
         symbols[s] += 1
     print(symbols)

Way 3: Counter

    symbols = Counter(inp_str.lower())
    print(symbols)

Upvotes: 0

karthik
karthik

Reputation: 34

Function takes input as string and counts the character and stores them in a dictionary

from typing import Dict


char_dict = {} #type: Dict[str, int]


def char_count(string: str) -> dict:
    new_string = string.lower()
    for c in new_string:
        if c in char_dict:
            char_dict[c] += 1
        else:
            char_dict[c] = 1
    return char_dict


if __name__ == "__main__":
    UserString = input("Enter Input String: ")
    CharCount = char_count(UserString)
    print("Characters Count: ", CharCount)

Example:

Enter Input String: Python programming is fun

Characters Count:  {'p': 2, 'y': 1, 't': 1, 'h': 1, 'o': 2, 'n': 3, ' ': 3, 'r': 2, 'g': 2, 'a': 1, 'm': 2, 'i': 2, 's': 1, 'f': 1, 'u': 1}

Upvotes: 0

Iain Shelvington
Iain Shelvington

Reputation: 32244

Use collections.Counter

dicx = collections.Counter(string.lower())

Upvotes: 2

Anurag Singh
Anurag Singh

Reputation: 126

You can iterate over string and update the dictionary accordingly and also there's no need of any count variable.

test_str = input().lower()
dicx = {} 
  
for i in test_str: 
    if i in dicx: 
        dicx[i] += 1
    else: 
        dicx[i] = 1

print(dicx)

Upvotes: 0

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