CODEWITHSUNDEEP
pythonstringlistdictionaryfrequency
kbaumzie
kbaumzie

Reputation: 3

Letter Occurrences and Frequency python

I need to create a list of letter occurrences from a list of words.

my list of words is ['song', 'boom', 'pow']

I want to count the letter occurrences in each word and then put them in a list in alphabetical order. If there isn't a letter in my word list that matches each letter in the alphabet, I still want it to print a 0 in the list.

Instead of typing out a string of 26 characters in the alphabet, I am using string.ascii_lowercase

I'm not really sure how to go about doing this.

I then I need to find out the letter occurrences in each word and which word[s] the letter is shown in.

Then output should look like:

[0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 4, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0]
'o' in 'song', 'boom', 'pow'
etc.

Upvotes: 0

Views: 425

Answers (3)

NPE
NPE

Reputation: 500327

The first part can be done like so:

In [12]: seq = ['song', 'boom', 'pow']

In [13]: c = collections.Counter(''.join(seq))

In [14]: [c.get(l, 0) for l in string.ascii_lowercase]
Out[14]: [0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 4, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0]

As to the second part, here is a hint:

In [23]: [w for w in seq if 'o' in w]
Out[23]: ['song', 'boom', 'pow']

Upvotes: 4

dawg
dawg

Reputation: 103824

Another way that seems natural to me:

>>> from string import ascii_lowercase
>>> words= ['song', 'boom', 'pow']
>>> s=''.join(words)
>>> [s.count(c) for c in ascii_lowercase]
[0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 4, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0]

For the second part, just use a nested loop:

for c in ascii_lowercase:
    li=[]
    for word in words:
        if c in word:
            li.append(word)
    if li:
        print '{} in {}'.format(c, ', '.join(li))

Prints:

b in boom
g in song
m in boom
n in song
o in song, boom, pow
p in pow
s in song
w in pow

Upvotes: 0

Padraic Cunningham
Padraic Cunningham

Reputation: 180401

from collections import OrderedDict
from string import ascii_lowercase
l = ['song', 'boom', 'pow']
od = OrderedDict(((k,0) for k in ascii_lowercase)) # create dict from alph with initial val of 0
for word in l:
    for let in word: 
        o[let] += 1 # increase value by 1 for each letter in the words
print(od.values()) # ordereddict keeps order so just print values
[0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 4, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0]


for k in od:
    for word in l:
        if k in word:
            print(k,word)
('b', 'boom')
('g', 'song')
('m', 'boom')
('n', 'song')
('o', 'song')
('o', 'boom')
('o', 'pow')
('p', 'pow')
('s', 'song')
('w', 'pow')

Process finished with exit code 0

Upvotes: 1

Related Questions