CODEWITHSUNDEEP
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Huibin Zhang
Huibin Zhang

Reputation: 1110

java assignment in char

I am learning java and the answer of one question seems to be wrong: question: Which of the following are legal?

char c = 0x1234;//A
char c = \u1234;//B
char c = '\u1234';//C

in the book the answer is C, but I think it should be both A and C. Anyone please verify that for me?

Upvotes: 2

Views: 2246

Answers (2)

Sotirios Delimanolis
Sotirios Delimanolis

Reputation: 279950

Both A and C are correct

char a = 0x1234;

The literal 0x1234 is a hex integer literal. Its value fits in the char primitive type, so it is valid;

char b = \u1234;//B

Is not valid notation and so won't compile.

char c = '\u1234';

char is

char: The char data type is a single 16-bit Unicode character. It has a minimum value of '\u0000' (or 0) and a maximum value of '\uffff' (or 65,535 inclusive).

So it's valid.

Upvotes: 6

Dark Knight
Dark Knight

Reputation: 8347

char c = 0x1234;//A -- Correct

as it's value begins with 0X it is a valid hexadecimal value. Hence Correct.

char c = \u1234;//B --- Incorrect

Not a valid u code, as it's not surrounded with''.

char c = '\u1234';//C -- Correct

it is valid u code and is correctly surrounded by '', hence it is correct too.

Upvotes: 1

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